40z+10-28-49=7z+20-17z

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Solution for 40z+10-28-49=7z+20-17z equation: 



40z+10-28-49=7z+20-17z

We move all terms to the left:

40z+10-28-49-(7z+20-17z)=0

We add all the numbers together, and all the variables

40z-(-10z+20)+10-28-49=0

We add all the numbers together, and all the variables

40z-(-10z+20)-67=0

We get rid of parentheses

40z+10z-20-67=0

We add all the numbers together, and all the variables

50z-87=0

We move all terms containing z to the left, all other terms to the right

50z=87

z=87/50

z=1+37/50

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