40z+10-28-49z=7z+20-17z

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Solution for 40z+10-28-49z=7z+20-17z equation: 



40z+10-28-49z=7z+20-17z

We move all terms to the left:

40z+10-28-49z-(7z+20-17z)=0

We add all the numbers together, and all the variables

40z-49z-(-10z+20)+10-28=0

We add all the numbers together, and all the variables

-9z-(-10z+20)-18=0

We get rid of parentheses

-9z+10z-20-18=0

We add all the numbers together, and all the variables

z-38=0

We move all terms containing z to the left, all other terms to the right

z=38

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