41(-8y+5)=-32y-26

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Solution for 41(-8y+5)=-32y-26 equation: 



41(-8y+5)=-32y-26

We move all terms to the left:

41(-8y+5)-(-32y-26)=0

We multiply parentheses

-328y-(-32y-26)+205=0

We get rid of parentheses

-328y+32y+26+205=0

We add all the numbers together, and all the variables

-296y+231=0

We move all terms containing y to the left, all other terms to the right

-296y=-231

y=-231/-296

y=231/296

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