41(y-10)=-42+y

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Solution for 41(y-10)=-42+y equation: 



41(y-10)=-42+y

We move all terms to the left:

41(y-10)-(-42+y)=0

We add all the numbers together, and all the variables

41(y-10)-(y-42)=0

We multiply parentheses

41y-(y-42)-410=0

We get rid of parentheses

41y-y+42-410=0

We add all the numbers together, and all the variables

40y-368=0

We move all terms containing y to the left, all other terms to the right

40y=368

y=368/40

y=9+1/5

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