41*2(3x*6)=95

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Solution for 41*2(3x*6)=95 equation: 



41*2(3x*6)=95

We move all terms to the left:

41*2(3x*6)-(95)=0

We add all the numbers together, and all the variables

41*2(+3x*6)-95=0

Wy multiply elements

492x^2(+-95=0

We use the square of the difference formula

492x^2(-95=0

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