41+(3x-10)=39

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Solution for 41+(3x-10)=39 equation: 



41+(3x-10)=39

We move all terms to the left:

41+(3x-10)-(39)=0

We add all the numbers together, and all the variables

(3x-10)+2=0

We get rid of parentheses

3x-10+2=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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