41+2(3x+6)=96

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Solution for 41+2(3x+6)=96 equation: 



41+2(3x+6)=96

We move all terms to the left:

41+2(3x+6)-(96)=0

We add all the numbers together, and all the variables

2(3x+6)-55=0

We multiply parentheses

6x+12-55=0

We add all the numbers together, and all the variables

6x-43=0

We move all terms containing x to the left, all other terms to the right

6x=43

x=43/6

x=7+1/6

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