41+5y-13=15y-12-2y

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Solution for 41+5y-13=15y-12-2y equation: 



41+5y-13=15y-12-2y

We move all terms to the left:

41+5y-13-(15y-12-2y)=0

We add all the numbers together, and all the variables

5y-(13y-12)+41-13=0

We add all the numbers together, and all the variables

5y-(13y-12)+28=0

We get rid of parentheses

5y-13y+12+28=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5

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