41+7x=2(-x+4)-30

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Solution for 41+7x=2(-x+4)-30 equation:



41+7x=2(-x+4)-30
We move all terms to the left:
41+7x-(2(-x+4)-30)=0
We add all the numbers together, and all the variables
7x-(2(-1x+4)-30)+41=0
We calculate terms in parentheses: -(2(-1x+4)-30), so:
2(-1x+4)-30
We multiply parentheses
-2x+8-30
We add all the numbers together, and all the variables
-2x-22
Back to the equation:
-(-2x-22)
We get rid of parentheses
7x+2x+22+41=0
We add all the numbers together, and all the variables
9x+63=0
We move all terms containing x to the left, all other terms to the right
9x=-63
x=-63/9
x=-7

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