41+7x=2(-x+4)-30

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Solution for 41+7x=2(-x+4)-30 equation: 



41+7x=2(-x+4)-30

We move all terms to the left:

41+7x-(2(-x+4)-30)=0

We add all the numbers together, and all the variables

7x-(2(-1x+4)-30)+41=0



We calculate terms in parentheses: -(2(-1x+4)-30), so:

2(-1x+4)-30

We multiply parentheses

-2x+8-30

We add all the numbers together, and all the variables

-2x-22

Back to the equation:

-(-2x-22)



We get rid of parentheses

7x+2x+22+41=0

We add all the numbers together, and all the variables

9x+63=0

We move all terms containing x to the left, all other terms to the right

9x=-63

x=-63/9

x=-7

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