41-(2c+3)=4(c+6)

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Solution for 41-(2c+3)=4(c+6) equation: 



41-(2c+3)=4(c+6)

We move all terms to the left:

41-(2c+3)-(4(c+6))=0

We get rid of parentheses

-2c-(4(c+6))-3+41=0



We calculate terms in parentheses: -(4(c+6)), so:

4(c+6)

We multiply parentheses

4c+24

Back to the equation:

-(4c+24)



We add all the numbers together, and all the variables

-2c-(4c+24)+38=0

We get rid of parentheses

-2c-4c-24+38=0

We add all the numbers together, and all the variables

-6c+14=0

We move all terms containing c to the left, all other terms to the right

-6c=-14

c=-14/-6

c=2+1/3

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