41-(2c+3)=4(c+6)+c

Solution for 41-(2c+3)=4(c+6)+c equation:

Simplifying
41 + -1(2c + 3) = 4(c + 6) + c

Reorder the terms:
41 + -1(3 + 2c) = 4(c + 6) + c
41 + (3 * -1 + 2c * -1) = 4(c + 6) + c
41 + (-3 + -2c) = 4(c + 6) + c

Combine like terms: 41 + -3 = 38
38 + -2c = 4(c + 6) + c

Reorder the terms:
38 + -2c = 4(6 + c) + c
38 + -2c = (6 * 4 + c * 4) + c
38 + -2c = (24 + 4c) + c

Combine like terms: 4c + c = 5c
38 + -2c = 24 + 5c

Solving
38 + -2c = 24 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
38 + -2c + -5c = 24 + 5c + -5c

Combine like terms: -2c + -5c = -7c
38 + -7c = 24 + 5c + -5c

Combine like terms: 5c + -5c = 0
38 + -7c = 24 + 0
38 + -7c = 24

Add '-38' to each side of the equation.
38 + -38 + -7c = 24 + -38

Combine like terms: 38 + -38 = 0
0 + -7c = 24 + -38
-7c = 24 + -38

Combine like terms: 24 + -38 = -14
-7c = -14

Divide each side by '-7'.
c = 2

Simplifying
c = 2