41-(2c=3)=(c+6)+c

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Solution for 41-(2c=3)=(c+6)+c equation: 



41-(2c=3)=(c+6)+c

We move all terms to the left:

41-(2c-(3))=0

We get rid of parentheses

-2c+3+41=0

We add all the numbers together, and all the variables

-2c+44=0

We move all terms containing c to the left, all other terms to the right

-2c=-44

c=-44/-2

c=+22

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