41-5z=2(z-4)

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Solution for 41-5z=2(z-4) equation: 



41-5z=2(z-4)

We move all terms to the left:

41-5z-(2(z-4))=0



We calculate terms in parentheses: -(2(z-4)), so:

2(z-4)

We multiply parentheses

2z-8

Back to the equation:

-(2z-8)



We get rid of parentheses

-5z-2z+8+41=0

We add all the numbers together, and all the variables

-7z+49=0

We move all terms containing z to the left, all other terms to the right

-7z=-49

z=-49/-7

z=+7

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