41-d=3(d-5)

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Solution for 41-d=3(d-5) equation:



41-d=3(d-5)
We move all terms to the left:
41-d-(3(d-5))=0
We add all the numbers together, and all the variables
-1d-(3(d-5))+41=0
We calculate terms in parentheses: -(3(d-5)), so:
3(d-5)
We multiply parentheses
3d-15
Back to the equation:
-(3d-15)
We get rid of parentheses
-1d-3d+15+41=0
We add all the numbers together, and all the variables
-4d+56=0
We move all terms containing d to the left, all other terms to the right
-4d=-56
d=-56/-4
d=+14

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