41-q=3(q+5)

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Solution for 41-q=3(q+5) equation: 



41-q=3(q+5)

We move all terms to the left:

41-q-(3(q+5))=0

We add all the numbers together, and all the variables

-1q-(3(q+5))+41=0



We calculate terms in parentheses: -(3(q+5)), so:

3(q+5)

We multiply parentheses

3q+15

Back to the equation:

-(3q+15)



We get rid of parentheses

-1q-3q-15+41=0

We add all the numbers together, and all the variables

-4q+26=0

We move all terms containing q to the left, all other terms to the right

-4q=-26

q=-26/-4

q=6+1/2

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