41-r=3(r-5)

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Solution for 41-r=3(r-5) equation:



41-r=3(r-5)
We move all terms to the left:
41-r-(3(r-5))=0
We add all the numbers together, and all the variables
-1r-(3(r-5))+41=0
We calculate terms in parentheses: -(3(r-5)), so:
3(r-5)
We multiply parentheses
3r-15
Back to the equation:
-(3r-15)
We get rid of parentheses
-1r-3r+15+41=0
We add all the numbers together, and all the variables
-4r+56=0
We move all terms containing r to the left, all other terms to the right
-4r=-56
r=-56/-4
r=+14

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