41/20=x+1/(y+1/z) - solution

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Solution for 41/20=x+1/(y+1/z) equation:

D( x )

y+1/z = 0

y+1/z = 0

y+1/z = 0

y+z^-1 = 0

x naleu017Cy do R

x belongs to the empty set

41/20 = 1/(y+1/z)+x

x belongs to the empty set

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