41/5x=2

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Solution for 41/5x=2 equation: 



41/5x=2

We move all terms to the left:

41/5x-(2)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply all the terms by the denominator


-2*5x+41=0

Wy multiply elements

-10x+41=0

We move all terms containing x to the left, all other terms to the right

-10x=-41

x=-41/-10

x=4+1/10

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