41/6-n=72/3

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Solution for 41/6-n=72/3 equation: 



41/6-n=72/3

We move all terms to the left:

41/6-n-(72/3)=0

We add all the numbers together, and all the variables

-n+41/6-24=0

We add all the numbers together, and all the variables

-1n-24+41/6=0

We multiply all the terms by the denominator


-1n*6+41-24*6=0

We add all the numbers together, and all the variables

-1n*6-103=0

Wy multiply elements

-6n-103=0

We move all terms containing n to the left, all other terms to the right

-6n=103

n=103/-6

n=-17+1/6

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