41/6.n=72/3

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Solution for 41/6.n=72/3 equation: 



41/6.n=72/3

We move all terms to the left:

41/6.n-(72/3)=0



Domain of the equation: 6.n!=0

n!=0/6.

n!=0

n∈R



We add all the numbers together, and all the variables

41/6.n-24=0

We multiply all the terms by the denominator


-24*6.n+41=0

Wy multiply elements

-144n+41=0

We move all terms containing n to the left, all other terms to the right

-144n=-41

n=-41/-144

n=41/144

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