41/8(3x-4)=33

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Solution for 41/8(3x-4)=33 equation: 



41/8(3x-4)=33

We move all terms to the left:

41/8(3x-4)-(33)=0



Domain of the equation: 8(3x-4)!=0

x∈R



We multiply all the terms by the denominator


-33*8(3x-4)+41=0

Wy multiply elements

-264x(3+41=0

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