413+5x2-4=3+21x-22

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Solution for 413+5x2-4=3+21x-22 equation: 



413+5x^2-4=3+21x-22

We move all terms to the left:

413+5x^2-4-(3+21x-22)=0

We add all the numbers together, and all the variables

5x^2-(21x-19)+413-4=0

We add all the numbers together, and all the variables

5x^2-(21x-19)+409=0

We get rid of parentheses

5x^2-21x+19+409=0

We add all the numbers together, and all the variables

5x^2-21x+428=0

a = 5; b = -21; c = +428;
Δ = b2-4ac
Δ = -212-4·5·428
Δ = -8119
Delta is less than zero, so there is no solution for the equation

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