41=(2/5x)-7

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Solution for 41=(2/5x)-7 equation: 



41=(2/5x)-7

We move all terms to the left:

41-((2/5x)-7)=0



Domain of the equation: 5x)-7)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+2/5x)-7)+41=0

We multiply all the terms by the denominator


-((+2+41*5x)-7)=0



We calculate terms in parentheses: -((+2+41*5x)-7), so:

(+2+41*5x)-7

We add all the numbers together, and all the variables

(41*5x+2)-7

We get rid of parentheses

41*5x+2-7

We add all the numbers together, and all the variables

41*5x-5

Wy multiply elements

205x-5

Back to the equation:

-(205x-5)



We get rid of parentheses

-205x+5=0

We move all terms containing x to the left, all other terms to the right

-205x=-5

x=-5/-205

x=1/41

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