41=2(4r+5)-9

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Solution for 41=2(4r+5)-9 equation: 



41=2(4r+5)-9

We move all terms to the left:

41-(2(4r+5)-9)=0



We calculate terms in parentheses: -(2(4r+5)-9), so:

2(4r+5)-9

We multiply parentheses

8r+10-9

We add all the numbers together, and all the variables

8r+1

Back to the equation:

-(8r+1)



We get rid of parentheses

-8r-1+41=0

We add all the numbers together, and all the variables

-8r+40=0

We move all terms containing r to the left, all other terms to the right

-8r=-40

r=-40/-8

r=+5

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