41=3x-4(3x+10)

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Solution for 41=3x-4(3x+10) equation: 



41=3x-4(3x+10)

We move all terms to the left:

41-(3x-4(3x+10))=0



We calculate terms in parentheses: -(3x-4(3x+10)), so:

3x-4(3x+10)

We multiply parentheses

3x-12x-40

We add all the numbers together, and all the variables

-9x-40

Back to the equation:

-(-9x-40)



We get rid of parentheses

9x+40+41=0

We add all the numbers together, and all the variables

9x+81=0

We move all terms containing x to the left, all other terms to the right

9x=-81

x=-81/9

x=-9

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