41=4x+3(x+2)

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Solution for 41=4x+3(x+2) equation: 



41=4x+3(x+2)

We move all terms to the left:

41-(4x+3(x+2))=0



We calculate terms in parentheses: -(4x+3(x+2)), so:

4x+3(x+2)

We multiply parentheses

4x+3x+6

We add all the numbers together, and all the variables

7x+6

Back to the equation:

-(7x+6)



We get rid of parentheses

-7x-6+41=0

We add all the numbers together, and all the variables

-7x+35=0

We move all terms containing x to the left, all other terms to the right

-7x=-35

x=-35/-7

x=+5

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