41=9/5c

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Solution for 41=9/5c equation: 



41=9/5c

We move all terms to the left:

41-(9/5c)=0



Domain of the equation: 5c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-(+9/5c)+41=0

We get rid of parentheses

-9/5c+41=0

We multiply all the terms by the denominator


41*5c-9=0

Wy multiply elements

205c-9=0

We move all terms containing c to the left, all other terms to the right

205c=9

c=9/205

c=9/205

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