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41=9/5c+32
We move all terms to the left:
41-(9/5c+32)=0
Domain of the equation: 5c+32)!=0We get rid of parentheses
c∈R
-9/5c-32+41=0
We multiply all the terms by the denominator
-32*5c+41*5c-9=0
Wy multiply elements
-160c+205c-9=0
We add all the numbers together, and all the variables
45c-9=0
We move all terms containing c to the left, all other terms to the right
45c=9
c=9/45
c=1/5
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