41=m+(m+3)+(m-6)

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Solution for 41=m+(m+3)+(m-6) equation: 



41=m+(m+3)+(m-6)

We move all terms to the left:

41-(m+(m+3)+(m-6))=0



We calculate terms in parentheses: -(m+(m+3)+(m-6)), so:

m+(m+3)+(m-6)

We get rid of parentheses

m+m+m+3-6

We add all the numbers together, and all the variables

3m-3

Back to the equation:

-(3m-3)



We get rid of parentheses

-3m+3+41=0

We add all the numbers together, and all the variables

-3m+44=0

We move all terms containing m to the left, all other terms to the right

-3m=-44

m=-44/-3

m=14+2/3

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