41x+100=(14x-3)

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Solution for 41x+100=(14x-3) equation: 



41x+100=(14x-3)

We move all terms to the left:

41x+100-((14x-3))=0



We calculate terms in parentheses: -((14x-3)), so:

(14x-3)

We get rid of parentheses

14x-3

Back to the equation:

-(14x-3)



We get rid of parentheses

41x-14x+3+100=0

We add all the numbers together, and all the variables

27x+103=0

We move all terms containing x to the left, all other terms to the right

27x=-103

x=-103/27

x=-3+22/27

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