41x+14=6(6x+1)+5x+8

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Solution for 41x+14=6(6x+1)+5x+8 equation: 



41x+14=6(6x+1)+5x+8

We move all terms to the left:

41x+14-(6(6x+1)+5x+8)=0



We calculate terms in parentheses: -(6(6x+1)+5x+8), so:

6(6x+1)+5x+8

We add all the numbers together, and all the variables

5x+6(6x+1)+8

We multiply parentheses

5x+36x+6+8

We add all the numbers together, and all the variables

41x+14

Back to the equation:

-(41x+14)



We get rid of parentheses

41x-41x-14+14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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