41x+3+70=77x+1

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Solution for 41x+3+70=77x+1 equation: 



41x+3+70=77x+1

We move all terms to the left:

41x+3+70-(77x+1)=0

We add all the numbers together, and all the variables

41x-(77x+1)+73=0

We get rid of parentheses

41x-77x-1+73=0

We add all the numbers together, and all the variables

-36x+72=0

We move all terms containing x to the left, all other terms to the right

-36x=-72

x=-72/-36

x=+2

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