41x+33=5(7x+6)+6x+3

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Solution for 41x+33=5(7x+6)+6x+3 equation: 



41x+33=5(7x+6)+6x+3

We move all terms to the left:

41x+33-(5(7x+6)+6x+3)=0



We calculate terms in parentheses: -(5(7x+6)+6x+3), so:

5(7x+6)+6x+3

We add all the numbers together, and all the variables

6x+5(7x+6)+3

We multiply parentheses

6x+35x+30+3

We add all the numbers together, and all the variables

41x+33

Back to the equation:

-(41x+33)



We get rid of parentheses

41x-41x-33+33=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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