42(2/7x)-42(7/3)=42(3x+1/2)

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Solution for 42(2/7x)-42(7/3)=42(3x+1/2) equation: 



42(2/7x)-42(7/3)=42(3x+1/2)

We move all terms to the left:

42(2/7x)-42(7/3)-(42(3x+1/2))=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

42(+2/7x)-(42(+3x+1/2))-42(+7/3)=0

We add all the numbers together, and all the variables

42(+2/7x)-(42(+3x+1/2))-14=0

We multiply parentheses

84x-(42(+3x+1/2))-14=0

We multiply all the terms by the denominator


84x*2))-(42(+3x+1-14*2))=0

We add all the numbers together, and all the variables

84x*2))-(42(3x-27))=0

We add all the numbers together, and all the variables

84x*2))-(42(3x=0

Wy multiply elements

168x^2=0

a = 168; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·168·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{336}=0$

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