42+(12x-4)=17x+18

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Solution for 42+(12x-4)=17x+18 equation: 



42+(12x-4)=17x+18

We move all terms to the left:

42+(12x-4)-(17x+18)=0

We get rid of parentheses

12x-17x-4-18+42=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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