42+(2z-30)+(z+15)=180

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Solution for 42+(2z-30)+(z+15)=180 equation: 



42+(2z-30)+(z+15)=180

We move all terms to the left:

42+(2z-30)+(z+15)-(180)=0

We add all the numbers together, and all the variables

(2z-30)+(z+15)-138=0

We get rid of parentheses

2z+z-30+15-138=0

We add all the numbers together, and all the variables

3z-153=0

We move all terms containing z to the left, all other terms to the right

3z=153

z=153/3

z=51

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