42+(z-5)=4(6z-8)

Solution for 42+(z-5)=4(6z-8) equation:

42+(z-5)=4(6z-8)

We move all terms to the left:

42+(z-5)-(4(6z-8))=0

We get rid of parentheses

z-(4(6z-8))-5+42=0


We calculate terms in parentheses: -(4(6z-8)), so:

4(6z-8)

We multiply parentheses

24z-32

Back to the equation:

-(24z-32)


We add all the numbers together, and all the variables

z-(24z-32)+37=0

We get rid of parentheses

z-24z+32+37=0

We add all the numbers together, and all the variables

-23z+69=0

We move all terms containing z to the left, all other terms to the right

-23z=-69

z=-69/-23

z=+3