42+3x=6(x+2)+3x

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Solution for 42+3x=6(x+2)+3x equation: 



42+3x=6(x+2)+3x

We move all terms to the left:

42+3x-(6(x+2)+3x)=0



We calculate terms in parentheses: -(6(x+2)+3x), so:

6(x+2)+3x

We add all the numbers together, and all the variables

3x+6(x+2)

We multiply parentheses

3x+6x+12

We add all the numbers together, and all the variables

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

3x-9x-12+42=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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