42+5y-11=14y-12-2y

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Solution for 42+5y-11=14y-12-2y equation: 



42+5y-11=14y-12-2y

We move all terms to the left:

42+5y-11-(14y-12-2y)=0

We add all the numbers together, and all the variables

5y-(12y-12)+42-11=0

We add all the numbers together, and all the variables

5y-(12y-12)+31=0

We get rid of parentheses

5y-12y+12+31=0

We add all the numbers together, and all the variables

-7y+43=0

We move all terms containing y to the left, all other terms to the right

-7y=-43

y=-43/-7

y=6+1/7

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