42-(2c+4)=(c+6)+c

Solution for 42-(2c+4)=(c+6)+c equation:

42-(2c+4)=(c+6)+c

We move all terms to the left:

42-(2c+4)-((c+6)+c)=0

We get rid of parentheses

-2c-((c+6)+c)-4+42=0


We calculate terms in parentheses: -((c+6)+c), so:

(c+6)+c

We add all the numbers together, and all the variables

c+(c+6)

We get rid of parentheses

c+c+6

We add all the numbers together, and all the variables

2c+6

Back to the equation:

-(2c+6)


We add all the numbers together, and all the variables

-2c-(2c+6)+38=0

We get rid of parentheses

-2c-2c-6+38=0

We add all the numbers together, and all the variables

-4c+32=0

We move all terms containing c to the left, all other terms to the right

-4c=-32

c=-32/-4

c=+8