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42-(3c+4)=(c+7)+c
We move all terms to the left:
42-(3c+4)-((c+7)+c)=0
We get rid of parentheses
-3c-((c+7)+c)-4+42=0
We calculate terms in parentheses: -((c+7)+c), so:We add all the numbers together, and all the variables
(c+7)+c
We add all the numbers together, and all the variables
c+(c+7)
We get rid of parentheses
c+c+7
We add all the numbers together, and all the variables
2c+7
Back to the equation:
-(2c+7)
-3c-(2c+7)+38=0
We get rid of parentheses
-3c-2c-7+38=0
We add all the numbers together, and all the variables
-5c+31=0
We move all terms containing c to the left, all other terms to the right
-5c=-31
c=-31/-5
c=6+1/5
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