42-(3c+4)=2(c+4)+2

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Solution for 42-(3c+4)=2(c+4)+2 equation: 



42-(3c+4)=2(c+4)+2

We move all terms to the left:

42-(3c+4)-(2(c+4)+2)=0

We get rid of parentheses

-3c-(2(c+4)+2)-4+42=0



We calculate terms in parentheses: -(2(c+4)+2), so:

2(c+4)+2

We multiply parentheses

2c+8+2

We add all the numbers together, and all the variables

2c+10

Back to the equation:

-(2c+10)



We add all the numbers together, and all the variables

-3c-(2c+10)+38=0

We get rid of parentheses

-3c-2c-10+38=0

We add all the numbers together, and all the variables

-5c+28=0

We move all terms containing c to the left, all other terms to the right

-5c=-28

c=-28/-5

c=5+3/5

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