42-(3c+4)=2(c+4)+c

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Solution for 42-(3c+4)=2(c+4)+c equation: 


Simplifying
42 + -1(3c + 4) = 2(c + 4) + c

Reorder the terms:
42 + -1(4 + 3c) = 2(c + 4) + c
42 + (4 * -1 + 3c * -1) = 2(c + 4) + c
42 + (-4 + -3c) = 2(c + 4) + c

Combine like terms: 42 + -4 = 38
38 + -3c = 2(c + 4) + c

Reorder the terms:
38 + -3c = 2(4 + c) + c
38 + -3c = (4 * 2 + c * 2) + c
38 + -3c = (8 + 2c) + c

Combine like terms: 2c + c = 3c
38 + -3c = 8 + 3c

Solving
38 + -3c = 8 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
38 + -3c + -3c = 8 + 3c + -3c

Combine like terms: -3c + -3c = -6c
38 + -6c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
38 + -6c = 8 + 0
38 + -6c = 8

Add '-38' to each side of the equation.
38 + -38 + -6c = 8 + -38

Combine like terms: 38 + -38 = 0
0 + -6c = 8 + -38
-6c = 8 + -38

Combine like terms: 8 + -38 = -30
-6c = -30

Divide each side by '-6'.
c = 5

Simplifying
c = 5

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