42-(3c+4)=2(c+4+c

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Solution for 42-(3c+4)=2(c+4+c equation: 



42-(3c+4)=2(c+4+c

We move all terms to the left:

42-(3c+4)-(2(c+4+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(2(2c+4)+42=0

We get rid of parentheses

-3c-(2(2c+4)+42-4=0

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