42-(3c+4)=2(c+7)=c

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Solution for 42-(3c+4)=2(c+7)=c equation: 



42-(3c+4)=2(c+7)=c

We move all terms to the left:

42-(3c+4)-(2(c+7))=0

We get rid of parentheses

-3c-(2(c+7))-4+42=0



We calculate terms in parentheses: -(2(c+7)), so:

2(c+7)

We multiply parentheses

2c+14

Back to the equation:

-(2c+14)



We add all the numbers together, and all the variables

-3c-(2c+14)+38=0

We get rid of parentheses

-3c-2c-14+38=0

We add all the numbers together, and all the variables

-5c+24=0

We move all terms containing c to the left, all other terms to the right

-5c=-24

c=-24/-5

c=4+4/5

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