42-1(3c-4)=2(c+4)c

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Solution for 42-1(3c-4)=2(c+4)c equation: 



42-1(3c-4)=2(c+4)c

We move all terms to the left:

42-1(3c-4)-(2(c+4)c)=0



We calculate terms in parentheses: -(2(c+4)c), so:

2(c+4)c

We multiply parentheses

2c^2+8c

Back to the equation:

-(2c^2+8c)



We get rid of parentheses

-2c^2-1(3c-4)-8c+42=0

We add all the numbers together, and all the variables

-2c^2-8c-1(3c-4)+42=0

We move all terms containing c to the left, all other terms to the right

-2c^2-8c-1(3c-4)=-42

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