42-4z=2(z-3)

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Solution for 42-4z=2(z-3) equation: 



42-4z=2(z-3)

We move all terms to the left:

42-4z-(2(z-3))=0



We calculate terms in parentheses: -(2(z-3)), so:

2(z-3)

We multiply parentheses

2z-6

Back to the equation:

-(2z-6)



We get rid of parentheses

-4z-2z+6+42=0

We add all the numbers together, and all the variables

-6z+48=0

We move all terms containing z to the left, all other terms to the right

-6z=-48

z=-48/-6

z=+8

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