42-5x=3(2x+1)+4(x+1)+5

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Solution for 42-5x=3(2x+1)+4(x+1)+5 equation: 



42-5x=3(2x+1)+4(x+1)+5

We move all terms to the left:

42-5x-(3(2x+1)+4(x+1)+5)=0



We calculate terms in parentheses: -(3(2x+1)+4(x+1)+5), so:

3(2x+1)+4(x+1)+5

We multiply parentheses

6x+4x+3+4+5

We add all the numbers together, and all the variables

10x+12

Back to the equation:

-(10x+12)



We get rid of parentheses

-5x-10x-12+42=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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