42/3y+3=15

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Solution for 42/3y+3=15 equation: 



42/3y+3=15

We move all terms to the left:

42/3y+3-(15)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

42/3y-12=0

We multiply all the terms by the denominator


-12*3y+42=0

Wy multiply elements

-36y+42=0

We move all terms containing y to the left, all other terms to the right

-36y=-42

y=-42/-36

y=1+1/6

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