428+13x=2(19x+21)+2(15x-27)

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Solution for 428+13x=2(19x+21)+2(15x-27) equation: 



428+13x=2(19x+21)+2(15x-27)

We move all terms to the left:

428+13x-(2(19x+21)+2(15x-27))=0



We calculate terms in parentheses: -(2(19x+21)+2(15x-27)), so:

2(19x+21)+2(15x-27)

We multiply parentheses

38x+30x+42-54

We add all the numbers together, and all the variables

68x-12

Back to the equation:

-(68x-12)



We get rid of parentheses

13x-68x+12+428=0

We add all the numbers together, and all the variables

-55x+440=0

We move all terms containing x to the left, all other terms to the right

-55x=-440

x=-440/-55

x=+8

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